NYT Pips Hints & Answers for June 29, 2026

Jun 29, 2026

🚨 SPOILER WARNING

This page contains the final **answer** and the complete **solution** to today's NYT Pips puzzle. If you haven't attempted the puzzle yet and want to try solving it yourself first, now's your chance!

Click here to play today's official NYT Pips game first.

Want hints instead? Scroll down for progressive clues that won't spoil the fun.

SEE ALSO:

🎲 Today's Puzzle Overview

This easy NYT Pips from Ian Livengood feels like a gentle on‑ramp. You’ll spot the equals pair right away — two cells that must match, and only the [0,0] domino can satisfy it, giving you an instant placement. From there, a single‑cell sum‑2 pins a 2 in the lower left, while the tempting sum‑15 column asks how to make 15 with three tiles. The domino bag hands you a pair of 5s plus an extra 5 from a 6‑5 tile, so the solution clicks into place with a satisfying symmetry. A greater‑2 region (sum >2) across three cells then resolves the final two dominos: a [1,1] and a strategically oriented [0,3].

Rodolfo Kurchan’s medium puzzle replaces easy giveaways with a web of single‑cell “greater” constraints. As you scan, you’ll notice that almost every row‑2 cell has a minimum value: [2,0] >2, [2,1] >3, [2,2] >4. These force a tight ladder of pips. The real spark comes from the sum‑7 region: a 1 in one of its cells forces a 6 next door, which then cascades into a chain reaction that fills the right side. Kurchan keeps the dominoes lean — every tile has a zero on one end except [1,1] and [5,1] — so you’re constantly trading off which zero goes where.

The hard puzzle, also by Kurchan, is a masterclass in constraint weaving. A solo sum‑6 cell at the bottom left immediately hands you a 6 and a 1, which triggers a sum‑3 pair and feeds a sum‑16 column. That column demands a 6‑5 pairing that ripples upward. Meanwhile, a four‑cell equals region all the way along row 3 must be identical — and once you deduce that the far‑right cell is a 4 (from a sum‑16 row above), the entire strip locks into 4s. The board becomes a domino‑by‑domino proof, with two more sum‑16 regions, a sum‑3 trio, and a greater‑9 pair all falling into place as you tick off each forced move.

💡 Progressive Hints

Try these hints one at a time. Each hint becomes more specific to help you solve it yourself!

💡 Hint 1: Spot the forced match
Look for an equals region — two cells that must hold the same pip number. Only one domino in your set can satisfy that immediately, so start there.
💡 Hint 2: Pinned values in the corners
The single‑cell sum‑2 at [2,0] locks a 2. The sum‑15 column on the right (cells [2,3], [3,3], [4,3]) naturally wants three 5s — check your [5,5] domino.
💡 Hint 3: Complete placement
Place [0,0] at [0,1][0,2] for the equals region. The [3,2] domino goes across [1,0] (3) and [2,0] (2). [5,5] fills [3,3][4,3]. The [0,3] domino covers [3,2] (0) and [3,1] (3). [6,5] sits at [1,3] (6) and [2,3] (5). Finally, [1,1] completes [3,0][4,0] (both 1).
💡 Hint 1: Honor the minimums
The board is dotted with single‑cell “greater” constraints — each demands its cell’s sum must exceed a given number. Tackle those one‑cell regions first to set baseline values.
💡 Hint 2: The sum‑7 catalyst
The greater‑0 cell at [0,4] wants at least a 1, pushing you to place the [1,1] domino there. Its partner [1,4] then forces the sum‑7 neighbor to a 6 at [2,4]. The increasing greater chain in row 2 will point you to a 5 at [2,2].
💡 Hint 3: Final layout
Place [1,1] at [0,4][1,4] (1 and 1). The sum‑7 needs [6,0] at [2,4] (6) with 0 at [3,4]. [3,0] domino covers [0,6][1,6] (3 and 0), setting up sum‑2 at [1,6][2,6] — place [2,0] at [2,6] (2) and 0 at [3,6]. [5,1] fills [2,2] (5) and [1,2] (1), while [4,0] covers [2,1] (4) and [3,1] (0). Finally [1,4] completes [1,0] (1) and [2,0] (4).
💡 Hint 1: Find the lone anchors
Begin by locating single‑cell sum regions — a lone cell forced to an exact pip is a powerful entry point. One such cell sits in the bottom left and dictates a 6.
💡 Hint 2: The 6‑1 domino unlocks a pair
The sum‑6 cell at [3,0] demands a 6, so the [1,6] domino places 6 there and a 1 at [3,1]. That feeds directly into the sum‑3 region covering [3,1] and [4,1], forcing a 2 at [4,1].
💡 Hint 3: Build the sum‑16 column
With [4,1]=2, its domino partner [4,2] becomes 5. The sum‑16 column at [2,2][3,2][4,2] now has [4,2]=5, so the remaining two cells must total 11. The [6,5] domino fits perfectly: 6 at [2,2], 5 at [3,2].
💡 Hint 4: The equals row and sum‑16 row
A sum‑16 row at [0,6][1,6][2,6] needs 5+5+6 — the [5,5] domino covers the two 5s, while [6,4] puts a 6 at [2,6] and a 4 at [3,6]. That 4 triggers the four‑cell equals region along row 3 (cols 3‑6), forcing all cells there to be 4. The [4,4] and [1,4] dominos fill the remaining equals cells.
💡 Hint 5: Complete solution
[1,6] gives 6 to [3,0] and 1 to [3,1]. [2,5] places 2 at [4,1] and 5 at [4,2]. [6,5] fills [2,2] (6) and [3,2] (5). Equals run: [4,4] at [3,3][3,4] (4,4), [1,4] at [2,5] (1) and [3,5] (4), [6,4] at [2,6] (6) and [3,6] (4). [5,5] goes to [0,6][1,6] (5,5). [0,0] to [2,7][2,8] (0,0). [4,3] to [1,8] (4) and [1,7] (3). [3,0] to [2,3] (3) and [2,4] (0). [6,6] to [4,5][4,6] (6,6). [2,4] to [5,6] (2) and [5,7] (4). [3,3] to [5,2][5,3] (3,3).

🎨 Pips Solver

Jun 29, 2026

Click a domino to place it on the board. You can also click the board, and the correct domino will appear.

Final Answer & Complete Solution For Hard Level

The key to solving today's hard puzzle was identifying the placement for the critical dominoes highlighted in the starting grid. Once those were in place, the rest of the puzzle could be solved logically. See the final grid below to compare your solution.

Starting Position & Key First Steps

Pips hint for June 29, 2026 – hard level puzzle grid with critical first placements and strategy

This image shows the initial puzzle grid for the hard level, with a few critical first placements highlighted.

Final Answer: The Solved Grid for Hard Mode

NYT Pips June 29, 2026 hard puzzle full solution grid showing final answer with hints

Compare this final grid with your own solution to see the correct placement of all dominoes.

🔧 Step-by-Step Answer Walkthrough For Easy Level

1
Step 1: Equals region
The two‑cell equals region at [0,1] and [0,2] requires identical pips. The only domino with two equal pips is [0,0], so place it there — both cells become 0.
2
Step 2: Sum‑2 cell
The single‑cell sum‑2 at [2,0] forces a 2. The only domino containing a 2 is [3,2]. Place it so that [2,0] receives the 2 and its partner [1,0] gets the 3 (the cell is empty).
3
Step 3: Sum‑15 column
The sum‑15 region spanning [2,3], [3,3], and [4,3] asks for three numbers that add to 15. Three 5s is the only practical trio. The [5,5] domino fills [3,3] and [4,3] with 5s. The third 5 must go to [2,3]; use the [6,5] domino with 5 at [2,3] and 6 at the empty cell [1,3].
4
Step 4: Greater‑2 region
The greater‑2 region (sum must exceed 2) includes [3,0], [3,1], [4,0]. Two dominos remain: [0,3] and [1,1]. If [1,1] occupies [3,0] and [4,0], those cells are each 1. To push the total above 2, [3,1] must be 3 — so place [0,3] with the 3 at [3,1] and the 0 at [3,2]. That satisfies the greater‑2 region (1+3+1 = 5 > 2).

🔧 Step-by-Step Answer Walkthrough For Medium Level

1
Step 1: Launch from [0,4] and sum‑7
Start with the single‑cell greater‑0 at [0,4]. Place the [1,1] domino so [0,4] gets a 1 (satisfying >0) and [1,4] gets the other 1. Now the sum‑7 region at [1,4] and [2,4] has [1,4]=1, so [2,4] must be 6. The only domino with a 6 is [6,0] — place it vertically with 6 at [2,4] and 0 at [3,4].
2
Step 2: Right‑side sum‑2 and greater‑1
The greater‑1 cell at [0,6] demands at least a 2. The [3,0] domino gives a 3 to [0,6] and a 0 to [1,6]. That sets the sum‑2 region at [1,6] and [2,6] with [1,6]=0, so [2,6] must be 2. Use the [2,0] domino, putting 2 at [2,6] and 0 at [3,6].
3
Step 3: Chain of greater cells in row 2
The single‑cell greater constraints in row 2 escalate: [2,2] must be >4, so only 5 or 6. The 6 is already used, so 5. The [5,1] domino places 5 at [2,2] and 1 at the empty cell [1,2].
4
Step 4: Fill [2,1] and [2,0]
[2,1] requires >3 (4 or above). The [4,0] domino fits, giving 4 to [2,1] and 0 to [3,1]. [2,0] must be >2; the remaining [1,4] domino provides a 4 at [2,0] and a 1 at [1,0], which also satisfies the greater‑0 at [1,0].
5
Step 5: Verify all regions
All cells are placed: sum‑7 is 1+6=7, sum‑2 is 0+2=2, and each greater condition is met (sums 1,3,4,4,5 respectively). The grid is complete.

🔧 Step-by-Step Answer Walkthrough For Hard Level

1
Step 1: Anchor on sum‑6
The single‑cell sum‑6 at [3,0] must be exactly 6. Use the [1,6] domino, placing the 6 at [3,0] and the 1 at [3,1].
2
Step 2: Sum‑3 pair and sum‑16 column
The sum‑3 region covering [3,1] and [4,1] now has [3,1]=1, so [4,1] must be 2. The [2,5] domino supplies a 2 for [4,1] and a 5 for [4,2]. The sum‑16 column at [2,2], [3,2], [4,2] contains [4,2]=5, so the remaining two cells must sum to 11. The [6,5] domino fits: 6 at [2,2] and 5 at [3,2] (6+5+5=16).
3
Step 3: Upper sum‑16 row
The sum‑16 row at [0,6], [1,6], [2,6] can be made with 5+5+6. Place [5,5] at [0,6] and [1,6] (5 each). Then [2,6] must be 6; use the [6,4] domino with 6 at [2,6] and 4 at [3,6].
4
Step 4: Equals row forced to 4
The equals region across [3,3], [3,4], [3,5], [3,6] now has [3,6]=4, so all four cells must be 4. Place [4,4] at [3,3] and [3,4] (both 4). Then [1,4] goes to [2,5] (1) and [3,5] (4).
5
Step 5: Remaining regions
Complete the rest: [0,0] at [2,7][2,8] (0,0) satisfies the sum‑3 trio there. [4,3] at [1,8] (4) and [1,7] (3) solves the sum‑4 cell and part of sum‑3. [3,0] places 3 at [2,3] and 0 at [2,4] (sum‑3 cell and sum‑1 partner). [6,6] at [4,5][4,6] (6,6) exceeds sum 9. [2,4] at [5,6][5,7] (2,4) makes sum 6. [3,3] at [5,2][5,3] (3,3) fulfills the final equals.

💡 Pro Tips for Similar Puzzles

Start with Constraints
Always begin with the most constrained regions - sum regions with small numbers or tight spaces.
Use Equal Regions
Use "equal" regions as anchors - they eliminate many possibilities quickly.
Work Systematically
Let the rules guide your placement rather than guessing randomly.
Double-Check
Verify each region's rules are satisfied before moving to the next.

🎓 Keep Learning & Improve