NYT Pips Hints & Answers for May 12, 2026

May 12, 2026

🚨 SPOILER WARNING

This page contains the final **answer** and the complete **solution** to today's NYT Pips puzzle. If you haven't attempted the puzzle yet and want to try solving it yourself first, now's your chance!

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🎲 Today's Puzzle Overview

Ian Livengood's easy grid opens on two independent footholds: an equals region of three cells forces a low double, while two sum-6 regions bracket the board, one solved immediately by a double-3, the other dependent on a domino split between empty cells. The solving chain is strictly linear once the equals keystone is placed, with the greater-3 constraint on [1,2] absorbing the only double-4.

Livengood's medium puzzle layers a top-row sum-12 constraint over a column-0 sum-9, with two separate equals pairs and a less-2 region that instantly locks a double-zero. The deduction splits into parallel threads: the less-2 domino forces the column-0 high-low split, while the sum-12 forces an ordered 1-4-4 distribution on the top row, converging on a greater-5 region that demands the highest available pips on the bottom row.

Rodolfo Kurchan's hard puzzle is a dense web of twelve dominoes on a 6x6 board. Today's NYT Pips hard features a sum-0 region that demands two zeros from separate dominoes, triggering a cascade through a sum-2 row and a greater-4 trigger. A four-cell equals region on the left locks the value 3 via a double-3 domino, while a second four-cell equals block in the lower right enforces a uniform 2 across a square. The solving chain relies on exact parity matches: tiny sums (0,1,2,3,4) interact with multiple greater-4 guards, forcing precise pip placement with very little slack.

💡 Progressive Hints

Try these hints one at a time. Each hint becomes more specific to help you solve it yourself!

💡 Hint 1: Spot the Keystone
Scan for a region that requires identical pip values across multiple cells—an equals constraint will be your entry point.
💡 Hint 2: The Row-of-Equals
The equals region spans [1,3], [1,4], and [2,3]. The two cells in row 1 must come from a single domino, forcing that domino to have twin pips. Once placed, all three cells must carry the same number.
💡 Hint 3: Full Assembly
Place the [1,1] domino horizontally on [1,3]-[1,4]. Then [2,3] must also be 1, so place [6,1] vertically with 6 at [2,2] and 1 at [2,3]. The sum-6 [0,4]-[0,5] takes the [3,3] domino (both 3). The other sum-6 [0,1]-[1,1] gets 2 from [3,2] at [0,0]-[0,1] (3 at [0,0]) and 4 from the [4,4] domino at [1,1]-[1,2], satisfying the greater-3 on [1,2].
💡 Hint 1: Obey the Cap
Start with the region that strictly caps pip values—a 'less-than' constraint will drastically narrow your options.
💡 Hint 2: Zero Anchor
The less-2 region at [2,1] and [2,2] can only be filled by a double-zero, the [0,0] domino. Placing it there sets off a chain reaction down column 0 and across the top row.
💡 Hint 3: Full Placement
Place [0,0] horizontally on [2,1]-[2,2]. Column 0's sum-9 forces [2,0]=6 (via [6,2] vertical, 2 at [3,0]) and [1,0]=3 (via [3,3] vertical, 3 at [0,0] and [1,0]). Top row sum-12: place [1,4] on [0,1]-[0,2] (1,4), then [4,3] vertical (4 at [0,3], 3 at [1,3]). Equals [1,3]-[2,3]: put [5,3] vertical (3 at [2,3], 5 at [3,3]). Bottom greater region and equals [3,0]-[3,1] complete with [2,4] horizontally on [3,1]-[3,2] (2,4).
💡 Hint 1: The Zero Sum
Zero in on the region that demands a total of zero—it forces two adjacent cells to be 0 and is the puzzle's tightest constraint.
💡 Hint 2: Dual Zeros
The sum-0 region at [3,3] and [3,4] compels both cells to be 0. Since no single [0,0] domino exists, you'll need two separate dominos to supply those zeros.
💡 Hint 3: Unlocking Row 2
The [0,2] domino can place a 0 at [3,3] with 2 at [2,3]; the [0,1] domino gives the other 0 at [3,4] with 1 at [2,4]. This sets up the sum-2 region on [2,4]-[2,5], forcing [2,5]=1 via [1,5] (which also puts 5 at [3,5] for a greater-4).
💡 Hint 4: The Big Equals
The large equals region covering [2,0],[2,1],[3,0],[4,0] all must share the same pip. The [3,3] domino placed vertically at [2,0]-[3,0] provides a matching pair (3 each). Then [3,0] horizontally on [2,1]-[2,2] gives 3 and 0, locking the common value to 3. [4,0] gets 3 from [3,5] vertical, which also places 5 at [5,0] (greater-4).
💡 Hint 5: Full Solution
Top sum-2 [0,2]-[0,3]: [1,1] domino (both 1). Sum-3 [1,2]-[2,2]: [1,2]=3 from [4,3] (with 4 at [1,3]), [2,2]=0. Sum-6 [1,3]-[2,3]: [2,3]=2 (from step 3) and [1,3]=4. Sum-0: [3,3]=0 via [0,2], [3,4]=0 via [0,1]; [2,4]=1, then sum-2 [2,4]-[2,5] yields [2,5]=1 from [1,5] (5 at [3,5]). Equals left: [2,0]=[3,0]=3, [2,1]=3, [2,2]=0, [4,0]=3 (via [3,5] with 5 at [5,0]). Lower equals [4,2]-[5,3] all 2: [2,5] vertical gives [4,2]=2, [3,2]=5 (empty); [2,1] horizontal at [5,1]-[5,2] (1 at [5,1] sum-1, 2 at [5,2]); [2,2] horizontal at [4,3]-[5,3] (both 2). Sum-4 [3,1]: [5,4] vertical (5 at [4,1] greater-4, 4 at [3,1]). All placed.

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May 12, 2026

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✅ Final Answer & Complete Solution For Hard Level

The key to solving today's hard puzzle was identifying the placement for the critical dominoes highlighted in the starting grid. Once those were in place, the rest of the puzzle could be solved logically. See the final grid below to compare your solution.

Starting Position & Key First Steps

Pips hint for May 12, 2026 – hard level puzzle grid with critical first placements and strategy

This image shows the initial puzzle grid for the hard level, with a few critical first placements highlighted.

Final Answer: The Solved Grid for Hard Mode

NYT Pips May 12, 2026 hard puzzle full solution grid showing final answer with hints

Compare this final grid with your own solution to see the correct placement of all dominoes.

🔧 Step-by-Step Answer Walkthrough For Easy Level

1
Step 1: Equals Keystone
The equals region on [1,3],[1,4],[2,3] forces two adjacent cells in row 1 to match. The only domino with identical pips is [1,1]; place it horizontally on [1,3]-[1,4] (both 1). Then [2,3] must also be 1.
2
Step 2: Filling the 1
With [2,3]=1, the only remaining domino containing a 1 is [6,1]. It must be placed vertically from [2,2] to [2,3], with 6 at [2,2] (empty) and 1 below. Now [2,2] satisfies its empty cell with 6.
3
Step 3: Double-3 Sum
The sum-6 region on [0,4]-[0,5] must add to 6 using available pips. The only suitable double is [3,3] (3+3=6). Place it horizontally there.
4
Step 4: Final Sum-6 and Greater
The remaining sum-6 at [0,1]-[1,1] still needs a total of 6. The [3,2] domino gives 3+2; place it vertically [0,0]-[0,1] with 3 at [0,0] (empty) and 2 at [0,1]. Then [1,1] must be 4. The [4,4] domino fits horizontally at [1,1]-[1,2] (both 4), meeting the greater-3 on [1,2].

🔧 Step-by-Step Answer Walkthrough For Medium Level

1
Step 1: Less-2 Locks Double-Zero
The less-2 region at [2,1] and [2,2] forces each cell to be <2. The only domino with two values under 2 is [0,0]. Place it horizontally there (both 0).
2
Step 2: Column 0 High-Low Split
Column 0's sum-9 region covers [1,0] and [2,0]. [2,0] can take a 6 from the [6,2] domino placed vertically (6 at [2,0], 2 at [3,0]). Then [1,0] must be 3 to sum to 9, so place [3,3] vertically at [0,0]-[1,0] (both 3). Now [0,0]=3.
3
Step 3: Top Row Sum-12
Top row sum-12 includes [0,0]=3 plus [0,1],[0,2],[0,3] summing to 9. The [1,4] domino (1+4) fits on [0,1]-[0,2] horizontally. Then [0,3] must be 4, so place [4,3] vertically (4 at [0,3], 3 at [1,3]).
4
Step 4: Equals Pair Row 1-2
The equals region [1,3]-[2,3] demands both cells to be 3. [1,3] already is 3 from step 3. Place [5,3] vertically: 3 at [2,3] and 5 at [3,3], setting up the greater region.
5
Step 5: Bottom Row Equals & Greater
The greater region at [3,2]-[3,3] has [3,3]=5; to satisfy both cells the [2,4] domino is placed horizontally on [3,1]-[3,2] with 2 and 4 (4 at [3,2]). The equals pair [3,0]-[3,1] already has [3,0]=2 from step 2, so [3,1]=2 completes it, locking the placing.

🔧 Step-by-Step Answer Walkthrough For Hard Level

1
Step 1: Sum-0 Zeros
The sum-0 region at [3,3]-[3,4] forces both cells to 0. No single [0,0] domino is available, so two dominos supply the zeros: place [0,2] vertically with 0 at [3,3] and 2 at [2,3]; place [0,1] vertically with 0 at [3,4] and 1 at [2,4].
2
Step 2: Sum-2 on Row 2
With [2,4]=1, the sum-2 region [2,4]-[2,5] requires [2,5]=1. The [1,5] domino provides that 1 and a 5 at [3,5] (satisfying greater-4 on [3,5]). Place it vertically.
3
Step 3: Left Equals Block
The four-cell equals region [2,0],[2,1],[3,0],[4,0] must be uniform. The [3,3] domino placed vertically at [2,0]-[3,0] gives 3 each. Then [3,0] horizontally on [2,1]-[2,2] gives 3 and 0, fixing the common value to 3. The final cell [4,0] needs 3 from [3,5] placed vertically (3 at [4,0], 5 at [5,0] for greater-4).
4
Step 4: Upper Sum-3 and Sum-6
The sum-3 region [1,2]-[2,2] now has [2,2]=0, so [1,2] must be 3. The [4,3] domino placed horizontally at [1,2]-[1,3] supplies 3 and 4. The sum-6 [1,3]-[2,3] then gets [1,3]=4 and [2,3]=2 (from step 1), perfectly summing to 6.
5
Step 5: Lower Equals and Sum-1
The lower equals block [4,2],[4,3],[5,2],[5,3] requires all 2s. Use [2,5] vertically at [4,2]=2 (with 5 at [3,2], empty). Place [2,1] horizontally at [5,1]-[5,2] giving 1 at [5,1] (sum-1) and 2 at [5,2]. Finally, [2,2] horizontally on [4,3]-[5,3] supplies the last two 2s.
6
Step 6: Remaining Pieces
Top sum-2 [0,2]-[0,3] takes [1,1] (both 1). The sum-4 at [3,1] needs 4, so place [5,4] vertically with 5 at [4,1] (greater-4) and 4 at [3,1]. All constraints satisfied.

💡 Pro Tips for Similar Puzzles

Start with Constraints
Always begin with the most constrained regions - sum regions with small numbers or tight spaces.
Use Equal Regions
Use "equal" regions as anchors - they eliminate many possibilities quickly.
Work Systematically
Let the rules guide your placement rather than guessing randomly.
Double-Check
Verify each region's rules are satisfied before moving to the next.

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