🔧 Step-by-Step Answer Walkthrough For Easy Level
Only two cells on the entire board are asked to add up to 1, and they sit side by side in the top-left purple region. With pips capped at 0 through 6, the only pair that can total 1 is a 0 and a 1 — so both halves of that region are accounted for before anything else moves.
The 1/2 tile stands vertically: 1 is the upper half in the purple sum 1 region's left cell, 2 is the lower half in the uncoloured free square directly below it. The 0/3 tile lies horizontally to the right of that: 0 is the left half in the purple sum 1 region's right cell, and its partner pip clears 2, so 3 is the right half sitting in the pink greater 2 cell.
The teal sum 9 column and the orange greater 1 cell share the top-right corner. The 2/5 tile lies horizontally across them: 5 is the left half in the teal sum 9 region's upper cell and 2 is the right half in the orange greater 1 cell, which satisfies both the sum's first digit and the greater-than test.
The teal sum 9 region still needs 4 under its 5. The 5/4 tile stands vertically on the right: 4 is the upper half in the teal sum 9 region's lower cell, completing 5 + 4, and 5 is the lower half in the blue sum 9 region's right cell. Then the 4/1 tile lies horizontally along the bottom: 1 is the left half in the uncoloured free square and 4 is the right half in the blue sum 9 region's left cell — 4 + 5 makes the second 9, and every constraint is satisfied.
🔧 Step-by-Step Answer Walkthrough For Medium Level
A single cell has to hold a pip above 4, and pips top out at 6, so the pink greater 4 cell at the top takes the 6. The tile it belongs to is the 0/6, which stands vertically: 6 is the upper half in the pink greater 4 cell, 0 is the lower half landing in the teal less 2 block.
All three cells of the purple block must show the same pip, so you need one value repeated across them. The 3/3 double stands vertically inside it: 3 upper in the purple block's top-right cell, 3 lower in its bottom-right cell. The third cell comes from the 3/0 tile, which stands vertically in the block's left cell — 3 upper in the purple block's bottom-left cell, 0 lower in the top-left cell of the teal less 2 block.
Seven cells have to stay under 2, and only one cell can afford the single 1 available. The 0/0 double stands vertically down the middle of the block, 0 upper and 0 lower, and the 0/1 tile stands vertically in the block's right column — 0 upper in its top-right cell, 1 lower in its bottom-right cell. Six zeros and a one is the only shape that fits.
The 4/0 tile stands vertically through the bottom of the teal block: 0 is the upper half in the teal block's bottom-centre cell — the last zero the less-2 rule needs — and 4 is the lower half in the uncoloured free square at the bottom-centre. Down the left edge the 1/4 tile stands vertically: 1 upper in the uncoloured free square on the bottom-left, 4 lower in the orange sum 4 region, which is a single cell that has to equal exactly 4.
Run the numbers: the teal less 2 block reads six zeros and a 1, comfortably under 2; the purple block reads 3, 3, 3; the pink cell holds 6 and the orange cell holds 4; the two uncoloured free squares take whatever the linking tiles give them, 1 and 4. Seven tiles, fourteen cells, every constraint met.
🔧 Step-by-Step Answer Walkthrough For Hard Level
The green sum 0 cell in the centre of the board must read exactly 0. It can only be covered by a tile coming down from the orange sum 6 pair above it — a tile reaching up from the pink sum 11 block below would have to carry a 0 into that block, which the 11 total cannot afford. The only tile that can donate a zero downward is the 5/0, so it stands vertically: 5 upper in the orange sum 6 pair's lower cell, 0 lower in the green sum 0 cell.
With 5 already in the orange pair's lower cell, the pair needs 1 above it. The 5/1 tile stands vertically: 5 is the upper half in the pink sum 5 cell at the top of the board — exactly the value that single cell demands — and 1 is the lower half in the orange sum 6 pair's upper cell, completing 1 + 5 = 6.
Three cells down the right edge must all show the same pip. Only 0 can be supplied three times from the tray, so the 0/0 double stands vertically in the column's middle and lower cells, and the 2/0 tile reaches down from the uncoloured free square at the top-right — 2 upper in the free square, 0 lower in the column's upper cell.
The purple greater 10 run is three cells that must total more than 10, and 3 + 6 + 2 = 11 does it. The 3/1 tile stands vertically at the far left: 3 upper in the run's left cell, 1 lower in the teal greater 6 column's upper cell. The 6/2 tile lies horizontally inside the run: 6 left in its middle cell, 2 right in its right cell. The teal column then needs 5 more from two cells, and the 4/2 tile stands vertically to finish it — 4 upper in the middle cell, 2 lower — for 1 + 4 + 2 = 7, safely past 6.
Bottom-left, the purple unequal block needs three all-different pips: the 4/1 tile stands vertically with 4 upper in its top-left cell and 1 lower in its bottom-left cell, and the 3/5 tile lies horizontally so that 3 is the left half in the block's bottom-right cell and 5 is the right half in the orange sum 5 cell. Bottom, the pink sum 11 block needs 3 + 4 + 4: the 4/3 tile stands vertically with 3 upper in its top-left cell and 4 lower in its bottom-left cell, while the 4/6 tile lies horizontally with 4 left in the pink block's bottom-right cell and 6 right in the teal equals block's bottom-left cell.
That teal equals block has two of its three cells spoken for by 6s, so the last one must be a 6 as well. The 6/6 double stands vertically in it: 6 upper in the block's top-right cell, 6 lower in its bottom-right cell. The bottom-right block reads 6, 6, 6 — twelve tiles placed, every sum, equals, unequal and greater-than constraint on the board satisfied.
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