NYT Pips Hints & Answers for May 1, 2026

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This page contains the final **answer** and the complete **solution** to today's NYT Pips puzzle. If you haven't attempted the puzzle yet and want to try solving it yourself first, now's your chance!

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Want hints instead? Scroll down for progressive clues that won't spoil the fun.

🎲 Today's Puzzle Overview

You open the easy grid and immediately spot a string of three cells along the top bound by an equals constraint — that triple-lock essentially gifts you the first domino (a pair of identical pips), and from there the puzzle cascades through a second equals duo and a sum-10 column. It's a light, satisfying solve where Ian Livengood's construction feels like a warm-up that rewards quick pattern recognition.

The medium difficulty, by Rodolfo Kurchan, quickly raises the stakes with a sparser layout. A sum-10 pair locks down the right column, while an unequal region straddling four cells and a greater-than duo force you to juggle domino candidates. You'll find that the equals region at the heart of the board demands a [0,0] domino, which then ripples outward, making the solution tightly interwoven.

Then the hard puzzle hits as a grid of almost entirely single-cell sum regions — a spectacular constraint set where every cell (except two empty spots and one equals pair) demands an exact pip value. As you work through this NYT Pips hard, you'll need to match a precise set of 15 dominoes to those fixed targets, with the zero-sum cells anchoring the entire solve. It's a deeply logical, domino-puzzle experience from constructor Rodolfo Kurchan.

💡 Progressive Hints

Try these hints one at a time. Each hint becomes more specific to help you solve it yourself!

💡 Hint 1: Follow the chain of equals

Scan the grid for regions that force cells to share the same pip value. The longest such region will immediately narrow down which domino must start the solve.

💡 Hint 2: Top-row triple

Focus on the three-cell equals region spanning (0,1) to (0,3). Every cell in that row must show the same number, so look for a domino with identical pips that can cover two of them. This also hints at which domino will extend into row 1.

💡 Hint 3: Full solve

Place domino [1,1] at (0,1)-(0,2). The remaining cell (0,3) must also be 1, so use domino [2,1] with the 1 at (0,3) and the 2 at (1,3). The sum‑10 column forces [6,6] at (0,0)-(1,0) and the [0,4] domino at (2,0)-(2,1) with 0 at (2,1) and 4 at (2,0). The less‑6 region is finished with [2,5] at (2,2)-(2,3) (5 at 2,2; 2 at 2,3).

💡 Hint 1: Sums and greater-thans

The medium grid uses sum targets, greater-than and an unequal region. Look for a column where two cells must add to 10 — that will force a specific domino early.

💡 Hint 2: Right-edge lock

The sum‑10 pair sits at (0,4) and (1,4). To reach exactly 10, a domino with two 5s is the only option, so place [5,5] there. Meanwhile, the greater‑1 cells at (0,2)-(0,3) need a domino with both pips above 1, which narrows things down.

💡 Hint 3: The full interlock

Place [5,5] at (0,4)-(1,4). The greater‑1 pair gets [2,2] at (0,2)-(0,3). That forces the equals region (1,2)-(1,3) to use the only remaining identical‑pip domino that fits: [0,0] horizontally. The sum‑5 cell at (2,0) must be 5, so [2,5] goes vertically (5 at 2,0; 2 at 2,1). The greater‑8 region (2,3)-(2,4) takes [6,5] (6 at 2,4; 5 at 2,3). The bottom‑left sum‑7 pair is filled with [3,3] at (3,0)-(3,1) and [4,4] at (4,0)-(4,1) giving 3+4=7. The unequal region completes with [6,1] at (3,2)-(4,2) (6 above, 1 below).

💡 Hint 1: A grid of exact numbers

Almost every cell is a single‑cell sum region. That means the required pip for each cell is already given — you just need to marry them to the right dominoes.

💡 Hint 2: Anchor on the zeros

Start by listing the forced pip values: the sum‑0 cells at (0,0), (2,5), and (4,5) must each be 0. The five dominoes with a zero pip are your anchors. The top‑left zero sits next to a sum‑4 cell, so look for a 0‑and‑4 domino.

💡 Hint 3: Three zero dominoes first

The (0,0)-(0,1) pair forces [0,4]. The zero at (2,5) is adjacent to (1,5), a sum‑1 cell, so [0,1] must cover both vertically. The bottom‑right zero at (4,5) pairs with (3,5) sum‑5, giving [0,5]. That accounts for three zero dominoes.

💡 Hint 4: Equals region demands zeros

The equals region (1,2)-(2,2) cannot use a single domino with two identical non-zero pips (none exist), so both cells must be 0. The remaining zero dominoes [0,2] and [0,3] supply those, with their other pips filling (2,1) and (1,1).

💡 Hint 5: Complete solution

Zero anchors: [0,4] at (0,0)-(0,1); [0,1] at (2,5)-(1,5); [0,5] at (4,5)-(3,5). Equals zeros: [0,3] at (1,2)-(1,1) and [0,2] at (2,2)-(2,1). Top row (0,2)-(0,3) takes [4,5] (5 then 4). Sum‑1 cells: [1,2] at (0,4)-(0,5); [1,4] at (1,4)-(2,4); [1,5] at (3,4)-(3,3). Sum‑3 cells: [2,3] at (2,0)-(1,0); [1,3] at (4,1)-(4,0); sum‑4/‑2 at row 3: [2,4] at (3,0)-(3,1); [3,5] at (3,2)-(4,2). Sum‑9: [3,4] at (1,3)-(2,3) pairs with the 5 at (3,3) from [1,5]. Last, [2,5] at (4,4)-(4,3).

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May 1, 2026

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✅ Final Answer & Complete Solution For Hard Level

The key to solving today's hard puzzle was identifying the placement for the critical dominoes highlighted in the starting grid. Once those were in place, the rest of the puzzle could be solved logically. See the final grid below to compare your solution.

Starting Position & Key First Steps

Pips hint for May 1, 2026 – hard level puzzle grid with critical first placements and strategy

This image shows the initial puzzle grid for the hard level, with a few critical first placements highlighted.

Final Answer: The Solved Grid for Hard Mode

NYT Pips May 1, 2026 hard puzzle full solution grid showing final answer with hints

Compare this final grid with your own solution to see the correct placement of all dominoes.

🔧 Step-by-Step Answer Walkthrough For Easy Level

Step 1: Spot the triple-equals

The equals region [0,1], [0,2], [0,3] demands that all three cells share the same pip value. Since only dominoes with identical pips can cover two of them, the [1,1] domino must be placed horizontally on (0,1)-(0,2).

Step 2: Extend the equals chain

[0,3] must also be 1, but no other identical-pip domino remains. The only adjacent free cell is [1,3], so the [2,1] domino goes vertically with its 1 at (0,3) and 2 at (1,3), completing the equals regions.

Step 3: Solve the sum-10 column

The sum‑10 region combines (1,0) and (2,0). The only remaining domino that can provide a 6 to (1,0) is [6,6], placed horizontally at (0,0)-(1,0). That forces (2,0) to be 4, so the [0,4] domino fits vertically at (2,0)-(2,1) with 4 at (2,0) and 0 at (2,1).

Step 4: Finish with the less-6 region

The last uncovered cells are (2,2) and (2,3), which belong to a less‑6 region with (2,1). Both must be under 6; the only remaining domino is [2,5], placed with 5 at (2,2) and 2 at (2,3). All constraints are satisfied.

🔧 Step-by-Step Answer Walkthrough For Medium Level

Step 1: Force the sum-10

Place [5,5] at (0,4)-(1,4) to satisfy the sum‑10 region. No other domino pair sums to 10, so this is forced.

Step 2: Greater-1 pair

The two greater‑1 cells in row 0, (0,2) and (0,3), are adjacent. They must be covered by a single domino with both pips >1. Of the available options, [2,2] is the most straightforward — place it horizontally there.

Step 3: Equals region resolves

Now the equals region at (1,2)-(1,3) must have identical pips. With [2,2] already used, the only remaining identical-pip domino that fits is [0,0]. Place it horizontally at (1,2)-(1,3).

Step 4: Sum-5 and greater-8

The sum‑5 cell at (2,0) requires a pip of 5. Domino [2,5] can supply that if we place its 5 at (2,0) and the 2 at the adjacent (2,1). The greater‑8 region (2,3)-(2,4) then takes [6,5] (6 at 2,4; 5 at 2,3).

Step 5: Left-column sums and unequal

The sum‑7 pair (3,0)+(4,0)=7 is achieved by placing [3,3] at (3,0)-(3,1) and [4,4] at (4,0)-(4,1) (3+4=7). The unequal region gets the last domino [6,1] placed vertically at (3,2)-(4,2) with 6 above and 1 below. All constraints are satisfied.

🔧 Step-by-Step Answer Walkthrough For Hard Level

Step 1: Read off the sum values

Every single-cell sum region tells you the exact pip it requires. Note the three sum‑0 cells: (0,0), (2,5), (4,5) must be 0. The equals pair (1,2)-(2,2) must also be identical.

Step 2: Three zero anchors

The zero at (0,0) is adjacent to a sum‑4 cell (0,1); the only domino with a 0 and 4 is [0,4] — place it at (0,0)-(0,1). The zero at (2,5) pairs with the sum‑1 cell (1,5); force [0,1] vertically at (2,5)-(1,5). The zero at (4,5) pairs with the sum‑5 cell (3,5); place [0,5] vertically at (4,5)-(3,5).

Step 3: Equals region forces two zeros

No domino has two identical non-zero pips, so the equals pair (1,2)-(2,2) must both be 0. That uses the remaining two zero-dominoes: [0,3] goes at (1,2)-(1,1) (0 at 1,2; 3 at 1,1) and [0,2] goes at (2,2)-(2,1) (0 at 2,2; 2 at 2,1).

Step 4: Fill the top row and sum-1 cells

The empty cell (0,3) and sum‑5 (0,2) are adjacent; place [4,5] there (4 at 0,3; 5 at 0,2). The sum‑1 cells need 1s: [1,2] at (0,4)-(0,5); [1,4] at (1,4)-(2,4); [1,5] at (3,4)-(3,3) (1 at 3,4; 5 at 3,3).

Step 5: Sum-3, sum-4, and sum-2 cells

The sum‑3 cell (1,0) pairs with (2,0) sum‑2 using [2,3] (3 at 1,0; 2 at 2,0). Sum‑3 (4,0) pairs with sum‑1 (4,1) using [1,3] (3 at 4,0; 1 at 4,1). Sum‑4 (3,1) pairs with sum‑2 (3,0) using [2,4] (4 at 3,1; 2 at 3,0). Sum‑3 (3,2) and sum‑5 (4,2) take [3,5] (3 at 3,2; 5 at 4,2).

Step 6: Complete the sum-9 and final domino

The sum‑9 region (2,3)-(3,3) gets [3,4] placed at (1,3)-(2,3) (3 at 1,3; 4 at 2,3), summing to 9 with the 5 already at (3,3). The last uncovered pair (4,4)-(4,3) receives [2,5] (2 at 4,4; 5 at 4,3). The board is solved.

💡 Pro Tips for Similar Puzzles

Start with Constraints

Always begin with the most constrained regions - sum regions with small numbers or tight spaces.

Use Equal Regions

Use "equal" regions as anchors - they eliminate many possibilities quickly.

Work Systematically

Let the rules guide your placement rather than guessing randomly.

Double-Check

Verify each region's rules are satisfied before moving to the next.

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NYT Pips Hints & Answers for May 1, 2026

🚨 SPOILER WARNING

🎲 Today's Puzzle Overview

💡 Progressive Hints

🎨 Pips Solver

✅ Final Answer & Complete Solution For Easy Level

Starting Position & Key First Steps

Final Answer: The Solved Grid for Easy Mode

✅ Final Answer & Complete Solution For Medium Level

Starting Position & Key First Steps

Final Answer: The Solved Grid for Medium Mode

✅ Final Answer & Complete Solution For Hard Level

Starting Position & Key First Steps

Final Answer: The Solved Grid for Hard Mode

🔧 Step-by-Step Answer Walkthrough For Easy Level

🔧 Step-by-Step Answer Walkthrough For Medium Level

🔧 Step-by-Step Answer Walkthrough For Hard Level

💡 Pro Tips for Similar Puzzles

🎓 Keep Learning & Improve

🧠 Strategy Guide

🎮 How to Play

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